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#11
29th November 2012, 10:01 PM
 Natch Project Supporter Senior Member Join Date: Jan 2011 Location: Nowhere near you. Posts: 5,075

ya ik butt who r u agen
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#12
29th November 2012, 10:26 PM
 HatCat Alpha Tester Project Supporter Senior Member Join Date: Feb 2007 Location: In my hat. Posts: 16,236

Huh?

What do you mean "again"? You never asked that question originally, therefore it's safe grounds to mark that question as invalid and not apt to answer either.
#13
30th November 2012, 04:15 AM
 Natch Project Supporter Senior Member Join Date: Jan 2011 Location: Nowhere near you. Posts: 5,075

k
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#14
30th November 2012, 09:57 PM
 HatCat Alpha Tester Project Supporter Senior Member Join Date: Feb 2007 Location: In my hat. Posts: 16,236

Tardo, the outdated (img)(/img) you stole off me doesn't even work on Google Chrome anymore.

If you can't learn how to troll properly I'll just use your username again XD

Or all I have to do is like, start talking about astrology, and then you won't shut up XD
#15
30th November 2012, 10:36 PM
 Natch Project Supporter Senior Member Join Date: Jan 2011 Location: Nowhere near you. Posts: 5,075

I like stars
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#16
1st December 2012, 12:10 AM
 HatCat Alpha Tester Project Supporter Senior Member Join Date: Feb 2007 Location: In my hat. Posts: 16,236

x^2 + bx + c == [x + sqrt(c)]^2
x^2 + bx + c == x^2 + 2*x*sqrt(c) + c
bx = 2x*sqrt(c)
x != 0 // simplifies uselessly to c == sqrt(c)
b = 2*sqrt(c)
2*sqrt(c) = b
4c = b^2
c = 0.25 * b^2

Add one-fourth the square of b to a binomial of the form (x^2 + bx) to transform it into a perfect square trinomial.

(Damn, I need to get back to that Sine of One Degree thing, I left all those 60+ sheets of ink-stained paper filled with my work on that back at DE xD)
#17
8th December 2012, 09:43 PM
 Natch Project Supporter Senior Member Join Date: Jan 2011 Location: Nowhere near you. Posts: 5,075

Finding the sine of one degree.
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#18
8th December 2012, 09:46 PM
 HatCat Alpha Tester Project Supporter Senior Member Join Date: Feb 2007 Location: In my hat. Posts: 16,236

Indeed, but these days I'm beginning to prefer:

Finding the product of two NxN matrices representing element-to-element broadcast mapping between two vector registers.
VR[vd] = VR[vs] * VR[vt] for the `rs & 0xF` bitmask subset of an SIMD machine command, == zero.

Supposedly there is a way to use a direct multiplication formula to solve for RSP opcodes like VMULz, VMACz etc. but I haven't looked into it yet.

.........

^^ that's just a spambot btw you damn fool
#19
9th December 2012, 07:14 PM
 Natch Project Supporter Senior Member Join Date: Jan 2011 Location: Nowhere near you. Posts: 5,075

I know it was a spambot :L

But spambots have feelings
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#20
9th December 2012, 10:11 PM
 HatCat Alpha Tester Project Supporter Senior Member Join Date: Feb 2007 Location: In my hat. Posts: 16,236

Quote:
 Originally Posted by voxelbufferOfficial I like stars
LOL! Ass.

The more I look back at some of your posts the more it cracks me up. You're that unchanged, unchangeable buffoon XD

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