is it safe?

[Mdkcheatz]

Originally Posted by rswedlow

Brandon, you're in college, solve this. log base x of x = -1.0

[omegadox]

hmmmmmmmmmmmmmmmm
X = LOLz

[Mdkcheatz]

Originally Posted by omegadox

hmmmmmmmmmmmmmmmm
X = LOLz

And LOLz = EmuCraze when it finally is mostly done....

[Mdkcheatz]

Originally Posted by xcdjy

So, pmming people concerning roms and where to find them was either deliberate, making you guilty... or accidental and you're going to apologise, right :S

Let's try this again

Basically I am a tad confused on your comment regarding private messages concerning queries on where to establish download sources for roms under the implication that I was a culprit?

Honestly, in regards to private messaging in general, no one has control over it nor is it available to the public. So what goes on tour stays on tour and does not really conjure any immediate threat to PJ64 Forums...

[CA5]

Originally Posted by Mdkcheatz

Let's try this again

Basically I am a tad confused on your comment regarding private messages concerning queries on where to establish download sources for roms under the implication that I was a culprit?

Yeah, doesn't take much to confuse you, really.

Originally Posted by Mdkcheatz

Honestly, in regards to private messaging in general, no one has control over it nor is it available to the public. So what goes on tour stays on tour and does not really conjure any immediate threat to PJ64 Forums...

Sure it doesn't. Unless you're sharing download links with a 'snoop' who's only signed up to see if you would, similar to what has happened on other forums

[HatCat]

Originally Posted by Mdkcheatz

x ~= .567

Originally Posted by omegadox

X = LOLz

Originally Posted by Mdkcheatz

LOLz = EmuCraze when it finally is ... done

Some skill with honesty I guess but I'd have to say nah.
Brandon if you want to try again, I'll give a hint: Find the real answer, and shove it up your ass.
None of those answers are compatible with that clue right? At least not yet

Yeah sorry if that was confusing how about...
Evaluate x when the logarithm of x whose base is x evaluates to -1. I doubt you have access to a calculator that can physically evaluate unatural bases.

Come on! I gave you like, a high school pre-algebra form of problem, and you couldn't even solve that. So I'm going easier. Dang stick to your game man.

[Mdkcheatz]

Originally Posted by rswedlow

Yeah sorry if that was confusing how about...
Evaluate x when the logarithm of x whose base is x evaluates to -1. I doubt you have access to a calculator that can physically evaluate unatural bases.

Come on! I gave you like, a high school pre-algebra form of problem, and you couldn't even solve that. So I'm going easier. Dang stick to your game man.

logarithms are not pre-algebra lol, more like college basic algebra, now don't try and degrade me with a false comparison :P

And hm, guess I calculated it wrong :S what is the answer?

[omegadox]

Leave it to the TI

[HatCat]

TI-83 to 84+ ain't going to help, nor is direct evaluation like a handheld calculator of any practical sort going to spit out both answers.

My bad I forgot about Virtual Chess there is a game once...

1.Nf3 d5 2.c4 dxc4 3.e3 b5 4.a4 c6 5.axb5 cxb5 6.b3 Nc6 7.bxc4 b4 8.d4 a5 9.d5 Nb8 10.c5 Nd7 11.Bb5 Qc7 12.Qc2 Nf6 13.Qc4 g6 14.e4 Bg7 15.O-O Nxe4 16.Qxe4 f5 17.Qe6 Bxa1 18.Re1 Qd8 19.Bg5 Ra6 20.d6 Rxd6 21.cxd6 Be5 22.Nxe5 Rf8 23.dxe7 Rf6 24.Qf7+ Rxf7 25.exd8=Q#

I just today played against the Vista engine as white..

1.Nf3 d5 2.c4 c6 3.e3 Nf6 4.Nc3 g6 5.cxd5 cxd5 6.Bb5+ Bd7 7.Qb3 e6 8.Bxd7+ Qxd7 9.Ne5 Qc7 10.d4 Bd6 11.Nb5 Qe7 12.Nxd6+ Kf8 13.Ndxf7 Rg8 14.Bd2 Nc6 15.Rc1 Rg7 16.Rxc6 bxc6 17.Bb4 c5 18.Bxc5 Qxc5 19.dxc5 Re8 20.c6 Rxf7 21.Nxf7 Kxf7 22.Qb7+ Kg8 23.c7 Nd7 24.c8=R Rxc8 25.Qxc8+ Nf8 26.Kd2 g5 27.Rc1 g4 28.Qe8 d4 29.Rc8 Kh8 30.Qxf8#

Better opening play includes 2...d4 3.b4 a5 = or 2...e6 {3.d4?! dxc4 4.e4 c5 =} 3.e3 Nf6 4.cxd5 exd5 5.d4 Be7 6.Bd3 Nc6 7.Nc3 O-O =. Alternatives for White include 2.e3 c5 3.b3 Nc6 4.Bb2 Nf6 5.Bb5 a6 = and 2.g3.

Originally Posted by Mdkcheatz

logarithms are not pre-algebra lol, more like college basic algebra, now don't try and degrade me with a false comparison :P

And hm, guess I calculated it wrong :S what is the answer?

I know your image was crap, though, in case you were joking.

Logarithms aren't algebra period. In fact well technically, as far as measuring, algebra doesn't really exist, nor does arithmetic or Calculus, it's all language, just boils down to pure quantitatives and our human inability to interact with them without creating symbols and designing a whole language for it.

Judging by your wording, you obviously vaguely have heard of a logarithm. If you're going to guess, make that an answer lol.

You want another hint? This is fun lol. Seeing as you barely knew how to solve for a monomial function albeit harder in algebra, I'll make some add-on: what's an inverse?

Find x when its inverse is x itself.

[CA5]

Originally Posted by rswedlow

I know your image was crap, though, in case you were joking.

XD, that's so damn cruel, it's funny.